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Find numbers a and b that satisfy the given condition in C++
Consider we have an integer n. Our task is to find two numbers a and b, where these three conditions will be satisfied.
- a mod b = 0
- a * b > n
- a / b < n
If no pair is found, print -1.
For an example, if the number n = 10, then a and b can be a = 90, b = 10. This satisfies given rules.
To solve this problem, we will follow these steps −
- Let b = n. a can be found using these three conditions
- a mod b = 0 when a is multiple of b
- a / b < n, so a / b = n – 1 which is < n
- (a * b > n) => a = n
Example
#include<iostream>
using namespace std;
void findAandB(int n) {
int b = n;
int a = b * (n - 1);
if (a * b > n && a / b < n) {
cout << "a: " << a << endl;
cout << "b: " << b;
}else
cout << -1 << endl;
}
int main() {
int n = 10;
findAandB(n);
}Output
a: 90 b: 10
Updated on: 01-Nov-2019
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