Find number of magical pairs of string of length L in C++.

Suppose we have two strings str1 and str2, we have to find a number of magical pairs of length L. Two strings will be magical if for every index I, the str1[i] < str2[i]. We have to count a number of pairs since the number is very large, then return the answer using modulo 109. The strings will hold only lowercase letters.

The approach is simple. As we can see, if the length is L = 1, and index i = 1 is holding ‘a’, in str1 then index i = 1 of str2 will hold from ‘b’ to ‘z’ so 25 combination, for next character it will be 24 combinations, so it will be 25 + 24 + . . . + 1 = 325. Now for L = 2, it will be 3252. For length L, it will be 325L. If it is very large, then find modulus 109.

Example

Live Demo

#include<iostream>
#include<cmath>
using namespace std;
int power(int a, unsigned int b, int mod) {
   int res = 1;
   a = a % mod;
   while (b > 0) {
      if (b & 1)
         res = (res * a) % mod;
      b = b >> 1;
      a = (a * a) % mod;
   }
   return res;
}
int main() {
   int L = 2, P = pow(10, 9);
   int res = power(325, L, P);
   cout << "Combinations: " << res << endl;
}