Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find normal at a given point on the curve in C++
Suppose we have a curve like y = x(A - x), we have to find the normal at a given point (x,y) on that curve. Here A is an integer number, x and y are also integers.
To solve this, we have the check that the given point is on the curve or not, if so, then find the differentiation of that curve, so it will be −
$$\frac{\text{d}y}{\text{d}x}=A-2x$$
Then put x and y into the dy/dx, then find the normal using this equation −
$$Y-y=-\lgroup\frac{\text{d}x}{\text{d}y}\rgroup*\lgroup X-x \rgroup$$
Example
#include<iostream>
using namespace std;
void getNormal(int A, int x, int y) {
int differentiation = A - x * 2;
if (y == (2 * x - x * x)) {
if (differentiation < 0)
cout << 0 - differentiation << "y = " << "x" << (0 - x) + (y * differentiation);
else if (differentiation > 0)
cout << differentiation << "y = " << "-x+" << x + differentiation * y;
else
cout << "x = " << x;
}
else
cout << "Not possible";
}
int main() {
int A = 5, x = 2, y = 0;
cout << "Equation of normal is: ";
getNormal(A, x, y);
}Output
Equation of normal is: 1y = -x+2
Updated on: 19-Dec-2019
88 Views
Advertisements