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Find missing number in a sequence in C#
Set a list.
List<int> myList = new List<int>(){1, 2, 3, 5, 8, 9};
Now, get the first and last elements −
int a = myList.OrderBy(x => x).First(); int b = myList.OrderBy(x => x).Last();
In a new list, get all the elements and use the Except to get the missing numbers −
List<int> myList2 = Enumerable.Range(a, b - a + 1).ToList(); List<int> remaining = myList2.Except(myList).ToList();
Let us see the complete code −
Example
using System.Collections.Generic; using System; using System.Linq; public class Program { public static void Main() { List<int> myList = new List<int>(){1, 2, 3, 5, 8, 9}; Console.WriteLine("Numbers... "); foreach(int val in myList) { Console.WriteLine(val); } int a = myList.OrderBy(x => x).First(); int b = myList.OrderBy(x => x).Last(); List<int> myList2 = Enumerable.Range(a, b - a + 1).ToList(); List<int> remaining = myList2.Except(myList).ToList(); Console.WriteLine("Remaining numbers... "); foreach (int res in remaining) { Console.WriteLine(res); } } }
Output
Numbers... 1 2 3 5 8 9 Remaining numbers... 4 6 7
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