Find max and min values in array of primitives using Java

This example shows how to search the minimum and maximum element in an array by using Collection.max() and Collection.min() methods of Collection class.

Example

 Live Demo

import java.util.Arrays;
import java.util.Collections;
public class Main {
   public static void main(String[] args) {
      Integer[] numbers = { 8, 2, 7, 1, 4, 9, 5};
      int min = (int) Collections.min(Arrays.asList(numbers));
      int max = (int) Collections.max(Arrays.asList(numbers));
      System.out.println("Min number: " + min);
      System.out.println("Max number: " + max);
   }
}

Output

The above code sample will produce the following result.

Min number: 1
Max number: 9

Another sample example of the minimum and the maximum element in an array.

Example

 Live Demo

public class HelloWorld {
   public static void main(String[] args) {
      int numbers[] = new int[]{8, 2, 7, 1, 4, 9, 5};
      int s = numbers[0];
      int l = numbers[0];
      for(int i = 1; i< numbers.length; i++) {
         if(numbers[i] > l)l = numbers[i];
         else if (numbers[i] < s)s = numbers[i];
      }
      System.out.println("Largest Number is : " + l);
      System.out.println("Smallest Number is : " + s);
   }
}

The above code sample will produce the following result.

Largest Number is : 9
Smallest Number is : 1

Ankith Reddy

Published on 01-Nov-2018 13:11:17

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