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Find if n can be written as product of k numbers in C++
Suppose we have a number N. We have another number k. We have to check the number can be represented using k numbers or not. Suppose a number 54, and k = 3, then it will print the numbers like [2, 3, 9], if it cannot be represented, then print that.
To solve this, we will find all prime factors of N, and store them into a vector, then to find k numbers greater than 1, we check the size of the vector is greater than k or not. If size is less than k, then return -1, otherwise print first k-1 factors and the last factor will be the product of all remaining numbers.
Example
#include<iostream>
#include<vector>
#include<cmath>
using namespace std;
int getKFactors(int n, int k){
int i;
vector<int> vec;
while(n % 2 == 0){
vec.push_back(2);
n = n/2; //reduce n by dividing this by 2
}
for(i = 3; i <= sqrt(n); i=i+2){ //i will increase by 2, to get only odd numbers
while(n % i == 0){
n = n/i;
vec.push_back(i);
}
}
if(n > 2){
vec.push_back(n);
}
if(vec.size() < k){
cout << "Cannot be represented";
return -1;
}
for (int i=0; i<k-1; i++)
cout << vec[i] << ", ";
int prod = 1;
for (int i=k-1; i<vec.size(); i++)
prod = prod*vec[i];
cout << prod << endl;
}
int main() {
int n = 54, k = 3;
getKFactors(n, k);
}Output
2, 3, 9
Updated on: 01-Nov-2019
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