Find duplicate in an array in O(n) and by using O(1) extra space in C++

Suppose we have a list of numbers from 0 to n-1. A number can be repeated as many as a possible number of times. We have to find the repeating numbers without taking any extra space. If the value of n = 7, and list is like [5, 2, 3, 5, 1, 6, 2, 3, 4, 5]. The answer will be 5, 2, 3.

To solve this, we have to follow these steps −

• for each element e in the list, do the following steps −
  • sign := A[absolute value of e]
  • if the sign is positive, then make it negative
  • Otherwise, it is a repetition.

Example

 Live Demo

#include<iostream>
#include<cmath>
using namespace std;
void findDuplicates(int arr[], int size) {
   for (int i = 0; i < size; i++) {
      if (arr[abs(arr[i])] >= 0)
         arr[abs(arr[i])] *= -1;
      else
         cout << abs(arr[i]) << " ";
   }
}
int main() {
   int arr[] = {5, 2, 3, 5, 1, 6, 2, 3, 4, 1};
   int n = sizeof(arr)/sizeof(arr[0]);
   findDuplicates(arr, n);
}

Output

5 2 3 1

Arnab Chakraborty

Published on 19-Dec-2019 07:45:36

• Related Questions & Answers
• Find duplicates in O(n) time and O(1) extra space - Set 1 in C++
• Find maximum in a stack in O(1) time and O(1) extra space in C++
• Rearrange positive and negative numbers in O(n) time and O(1) extra space in C++
• Find the maximum repeating number in O(n) time and O(1) extra space in Python
• Count frequencies of all elements in array in O(1) extra space and O(n) time in C++
• Find median of BST in O(n) time and O(1) space in C++
• Print n x n spiral matrix using O(1) extra space in C Program.
• Find median of BST in O(n) time and O(1) space in Python
• Print left rotation of array in O(n) time and O(1) space in C Program.
• Check for balanced parentheses in an expression - O(1) space - O(N^2) time complexity in C++
• Count Fibonacci numbers in given range in O(Log n) time and O(1) space in C++
• A product array puzzle (O(1) Space) in C++?
• Find duplicates in constant array with elements 0 to N-1 in O(1) space in C++
• Rearrange array in alternating positive & negative items with O(1) extra space in C++
• Check for balanced parentheses in an expression O(1) space O(N^2) time complexity in Python