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Find document in MongoDB where at least one item from an array is not in the other?
For this, set regex in MongoDB find(). Let us create a collection with documents −
> db.demo228.insertOne({"Subjects":["MongoDB","Java"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3fa51f03d395bdc213473b")
}
> db.demo228.insertOne({"Subjects":["MongoDB","Java","MySQL"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3fa52c03d395bdc213473c")
}Display all documents from a collection with the help of find() method −
> db.demo228.find();
This will produce the following output −
{ "_id" : ObjectId("5e3fa51f03d395bdc213473b"), "Subjects" : [ "MongoDB", "Java" ] }
{ "_id" : ObjectId("5e3fa52c03d395bdc213473c"), "Subjects" : [ "MongoDB", "Java", "MySQL" ] }Following is the query to find documents where at least one item from an array is not in the other −
> db.demo228.find({ "Subjects": /^(?!MongoDB|Java)/ });This will produce the following output −
{ "_id" : ObjectId("5e3fa52c03d395bdc213473c"), "Subjects" : [ "MongoDB", "Java", "MySQL" ] }
Updated on: 30-Mar-2020
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