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Find date record after a particular date from a column with VARCHAR type in MySQL
Let us first create a table. Here, we have set date as VARCHAR −
mysql> create table DemoTable1364 -> ( -> ShippingDate varchar(100) -> ); Query OK, 0 rows affected (0.87 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1364 values('01-09-2019 12:34:55');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1364 values('01-07-2018 17:10:00');
Query OK, 1 row affected (0.37 sec)
mysql> insert into DemoTable1364 values('24-09-2019 10:31:22');
Query OK, 1 row affected (0.24 sec)
mysql> insert into DemoTable1364 values('20-09-2018 13:00:00');
Query OK, 1 row affected (0.13 sec)Display all records from the table using select statement −
mysql> select * from DemoTable1364;
This will produce the following output −
+---------------------+ | ShippingDate | +---------------------+ | 01-09-2019 12:34:55 | | 01-07-2018 17:10:00 | | 24-09-2019 10:31:22 | | 20-09-2018 13:00:00 | +---------------------+ 4 rows in set (0.00 sec)
Here is the query to find date record after a particular date from a column with VARCHAR type −
mysql> select * from DemoTable1364
-> where str_to_date(ShippingDate,'%d-%m-%Y %H:%i:%s') > str_to_date('2019-09-21 10:31:20', '%Y-%m-%d %H:%i:%s');This will produce the following output −
+---------------------+ | ShippingDate | +---------------------+ | 24-09-2019 10:31:22 | +---------------------+ 1 row in set (0.00 sec)
Updated on: 08-Nov-2019
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