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Find area of parallelogram if vectors of two adjacent sides are given using C++.
Suppose we have two vectors for two adjacent sides of a parallelogram in the form $x\hat{i}+y\hat{j}+z\hat{k}$ Our task is to find the area of parallelogram. The area of parallelogram is magnitude of the cross product of two vectors. (|A × B|)
$$\rvert \vec{A}\times\vec{B}\rvert=\sqrt{\lgroup y_{1}*z_{2}-y_{2}*z_{1}\rgroup^{2}+\lgroup x_{1}*z_{2}-x_{2}*z_{1}\rgroup^{2}+\lgroup x_{1}*y_{2}-x_{2}*y_{1}\rgroup^{2}}$$
Example
#include<iostream>
#include<cmath>
using namespace std;
float area(float A[], float B[]) {
float area = sqrt(pow((A[1] * B[2] - B[1] * A[2]),2) + pow((A[0] * B[2] - B[0] * A[2]),2) + pow((A[0] * B[1] - B[0] * A[1]),2));
return area;
}
int main() {
float A[] = {3, 1, -2};
float B[] = {1, -3, 4};
float a = area(A, B);
cout << "Area = " << a;
}Output
Area = 17.3205
Updated on: 29-Oct-2019
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