# Find a number that divides maximum array elements in C++

In this tutorial, we are going to find the number that is divided into maximum elements in the given array.

Let's see the steps to solve the problem.

• Initialize the array and a variable to store the result.

• Iterate over the array.

• Initialize the counter variable.

• Iterate over the array again.

• Increment the counter if the current element is divisible by the array element.

• Update the result if the current count is maximum.

• Print the result.

## Example

Let's see the code.

Live Demo

#include <bits/stdc++.h>
using namespace std;
int numberWithMaximumMultiples(int arr[], int n) {
int result = -1;
for (int i = 0; i < n; i++) {
int count = 0;
for (int j = 0; j < n; j++) {
if (arr[i] % arr[j] == 0) {
count++;
}
}
if (count > result) {
result = count;
}
}
return result;
}
int main() {
int arr[] = {4, 24, 16, 3, 12, 28};
cout << numberWithMaximumMultiples(arr, 6) << endl;
return 0;
}

## Output

If you execute the above code, then you will get the following result.

4

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.