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Fetch domain name by passing name in MySQL?
To fetch domain name by passing name in MySQL, you can use substring_index(). Let us first create a table −
mysql> create table DemoTable ( UserId int NOT NULL AUTO_INCREMENT PRIMARY KEY, UserMailId varchar(200) ); Query OK, 0 rows affected (0.77 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable(UserMailId) values('John9989@facebook.com'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable(UserMailId) values('983773CS@yahoo.com'); Query OK, 1 row affected (0.23 sec) mysql> insert into DemoTable(UserMailId) values('Chris95@gmail.com'); Query OK, 1 row affected (0.20 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+--------+-----------------------+ | UserId | UserMailId | +--------+-----------------------+ | 1 | John9989@facebook.com | | 2 | 983773CS@yahoo.com | | 3 | Chris95@gmail.com | +--------+-----------------------+ 3 rows in set (0.00 sec)
Following is the query to fetch domain name by passing name in MySQL.
mysql> select UserId,UserMailId, substring_index(substring_index(UserMailId, '@', -1), '.', 1) AS `Domain_Name` from DemoTable;
This will produce the following output. Here, domain name is fetched −
+--------+-----------------------+-------------+ | UserId | UserMailId | Domain_Name | +--------+-----------------------+-------------+ | 1 | John9989@facebook.com | facebook | | 2 | 983773CS@yahoo.com | yahoo | | 3 | Chris95@gmail.com | gmail | +--------+-----------------------+-------------+ 3 rows in set (0.01 sec)
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