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Excel Sheet Column Title in C++
Suppose we have a positive integer; we have to find its corresponding column title as appear in an Excel sheet. So [1 : A], [2 : B], [26 : Z], [27 : AA], [28 : AB] etc.
So, if the input is like 28, then the output will be AB.
To solve this, we will follow these steps −
while n is non-zero, do −
n := n - 1
res := res + n mod 26 + ASCII of 'A'
n := n / 26
reverse the array res
return res
Example
Let us see the following implementation to get a better understanding −
#include <bits/stdc++.h> using namespace std; class Solution { public: string convertToTitle(int n) { string res; while(n){ res += (--n)%26 + 'A'; n /= 26; } reverse(res.begin(), res.end()); return res; } }; main(){ Solution ob; cout << (ob.convertToTitle(30)); }
Input
30
Output
AD
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