Euler and Hamiltonian Paths

MathematicsComputer EngineeringMCA

A graph is traversable if you can draw a path between all the vertices without retracing the same path. Based on this path, there are some categories like Euler’s path and Euler’s circuit which are described in this chapter.

Euler’s Path

An Euler’s path contains each edge of ‘G’ exactly once and each vertex of ‘G’ at least once. A connected graph G is said to be traversable if it contains an Euler’s path.


Euler’s Path

Euler’s Path = d-c-a-b-d-e.

Euler’s Circuit

In an Euler’s path, if the starting vertex is same as its ending vertex, then it is called an Euler’s circuit.


Euler's Circuit

Euler’s Path = a-b-c-d-a-g-f-e-c-a.

Euler’s Circuit Theorem

A connected graph ‘G’ is traversable if and only if the number of vertices with odd degree in G is exactly 2 or 0. A connected graph G can contain an Euler’s path, but not an Euler’s circuit, if it has exactly two vertices with an odd degree.

Note − This Euler path begins with a vertex of odd degree and ends with the other vertex of odd degree.


Euler's Circuit Theorem

Euler’s Path − b-e-a-b-d-c-a is not an Euler’s circuit, but it is an Euler’s path. Clearly it has exactly 2 odd degree vertices.

Note − In a connected graph G, if the number of vertices with odd degree = 0, then Euler’s circuit exists.

Hamiltonian Path

A connected graph is said to be Hamiltonian if it contains each vertex of G exactly once. Such a path is called a Hamiltonian path.


Hamiltonian Path

Hamiltonian Path − e-d-b-a-c.


  • Euler’s circuit contains each edge of the graph exactly once.
  • In a Hamiltonian cycle, some edges of the graph can be skipped.


Take a look at the following graph −

Hamiltonian Path Example

For the graph shown above −

  • Euler path exists – false
  • Euler circuit exists – false
  • Hamiltonian cycle exists – true
  • Hamiltonian path exists – true

G has four vertices with odd degree, hence it is not traversable. By skipping the internal edges, the graph has a Hamiltonian cycle passing through all the vertices.

Published on 23-Aug-2019 10:51:53