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Draw the state transition diagram over an alphabet Σ={a,b} that accepts the string starting with ‘ab’.

The formal definition of Deterministic Finite Automata (DFA) is as follows −

A DFA is a collection of 5-tuples as shown below −

**M=(Q, Σ, δ,q0,F)**

Where,

- Q: Finite set called states.
- Σ: Finite set called alphabets.
- δ: Q × Σ → Q is the transition function.
- q0 ∈ Q is the initial state.

The language is generated as given below −

L={ab,aba,abab,…….}

The transition diagram is as follows −

Here,

- D is a dead state.
- D is a transition state, which it can never escape. Such a state is called a trap state. It is called the dead state.

**ab**− q1 on’ a’ goes to q2 and q2 on ‘b’ goes to qf to reach final state. So, ab is accepted.**baa**− q1 on ‘b’ goes to D state, which is dead state. There is no way to reach the final state. So, baa is not accepted.

The transition table is as follows −

State/Input symbol | a | b |
---|---|---|

∈q1 | q2 | Dead state (D) |

q2 | Dead state (D) | qf |

qf | qf | qf |

D | - | - |

**Step 1**− q1 is an initial state on input a it goes to state q2 and on ‘b’ goes to dead state.**Step 2**− q2 on ‘a’ goes to dead state and on ‘b’ goes to qf which is the final state.**Step 3**− qf is the final state on input ‘a’ and ‘b’ goes to qf state itself.**Step 4**− D is a dead state, there is no path from D to any state.

Design a DFA which accepts a language over the alphabets Σ = {a, b} such that L is the set of all strings starting with ‘aba’.

All strings start with the substring “aba”.

Therefore, length of substring = 3.

Minimum number of states in the DFA = 3 + 2 = 5.

The language L= {aba,abaa,abaab,abaaba}

The transition diagram is as follows −

The transition table is as follows −

State/Input symbol | a | b |
---|---|---|

∈q0 | q1 | Dead state (D) |

q1 | Dead state (D) | q2 |

qf | qf | qf |

D | - | - |

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