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# Divisibility by 12 for a large number in C++ Program

In this tutorial, we are going to write a program that checks whether the given large number in string format is divisible by 12 or not.

We are going to use a little bit of math to solve this problem. If the number is divisible by 3 and 4, then the number will divisible by 12.

A number is divisible by 3 if the sum of its digits is divisible by 3.

A number is divisible by 4 if the last two digits of the number are divisible by 4.

We are going to utilize the above statements and complete the program.

## Example

Let's see the code.

#include <bits/stdc++.h> using namespace std; bool isNumberDivisibleBy12(string num) { if (num.length() >= 3) { int last_digit = (int)num[num.length() - 1]; if (last_digit % 2 != 0) { return 0; } int second_last_digit = (int)num[num.length() - 2]; int sum = 0; for (int i = 0; i < num.length(); i++) { sum += num[i]; } return (sum % 3 == 0 && (second_last_digit * 10 + last_digit) % 4 == 0); } else { int number_as_int = stoi(num); return number_as_int % 12 == 0; } } int main() { string num = "1212121212121212121212121212"; if (isNumberDivisibleBy12(num)) { cout << "Yes" << endl; } else { cout << "No" << endl; } return 0; }

## Output

If you execute the above program, then you will get the following result.

Yes

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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