Divide every element of one array by other array elements in C++ Program
In this tutorial, we are going to write a program that divides one array of elements by another array of elements.
Here, we are following a simple method to complete the problem. Let's see the steps to solve the problem.
Initialize the two arrays.
Iterate through the second array and find the product of the elements.
Iterate through the first array and divide each element with a product of the second array elements.
Example
Let's see the code.
Live Demo
#include <bits/stdc++.h>
using namespace std;
void divideArrOneWithTwo(int arr_one[], int arr_two[], int n, int m) {
int arr_two_elements_product = 1;
for (int i = 0; i < m; i++) {
if (arr_two[i] != 0) {
arr_two_elements_product = arr_two_elements_product * arr_two[i];
}
}
for (int i = 0; i < n; i++) {
cout << floor(arr_one[i] / arr_two_elements_product) << " ";
}
cout << endl;
}
int main() {
int arr_one[] = {32, 22, 4, 55, 6}, arr_two[] = {1, 2, 3};
divideArrOneWithTwo(arr_one, arr_two, 5, 3);
return 0;
}Output
If you run the above code, then you will get the following result.
5 3 0 9 1
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Published on 27-Jan-2021 12:48:52
