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Display default initial values of DataTypes in Java
To display default initial values of a datatype, you need to just declare a variable of the same datatype and display it.
The following is a Java program to display initial values of DataTypes.
Example
public class Demo {
boolean t;
byte b;
short s;
int i;
long l;
float f;
double d;
void Display() {
System.out.println("boolean (Initial Value) = " + t);
System.out.println("byte (Initial Value) = " + b);
System.out.println("short (Initial Value) = " + s);
System.out.println("int (Initial Value) = " + i);
System.out.println("long (Initial Value) = " + l);
System.out.println("float (Initial Value) = " + f);
System.out.println("double (Initial Value) = " + d);
}
public static void main(String[] args) {
Demo d = new Demo();
System.out.println("Displaying initial values...");
d.Display();
}
}Output
Displaying initial values... boolean (Initial Value) = false byte (Initial Value) = 0 short (Initial Value) = 0 int (Initial Value) = 0 long (Initial Value) = 0 float (Initial Value) = 0.0 double (Initial Value) = 0.0
In the above program, we have declared a variable with different datatypes.
boolean t; byte b; short s; int i; long l; float f; double d;
Now to get the default initial values, just print the variable declared above.
System.out.println("boolean (Initial Value) = " + t);
System.out.println("byte (Initial Value) = " + b);
System.out.println("short (Initial Value) = " + s);
System.out.println("int (Initial Value) = " + i);
System.out.println("long (Initial Value) = " + l);
System.out.println("float (Initial Value) = " + f);
System.out.println("double (Initial Value) = " + d);The above displays the default values.
Updated on: 26-Jun-2020
2K+ Views
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