Display default initial values of DataTypes in Java

Java 8Object Oriented ProgrammingProgramming

To display default initial values of a datatype, you need to just declare a variable of the same datatype and display it.

The following is a Java program to display initial values of DataTypes.

Example

 Live Demo

public class Demo {
   boolean t;
   byte b;
   short s;
   int i;
   long l;
   float f;
   double d;
   void Display() {
      System.out.println("boolean (Initial Value) = " + t);
      System.out.println("byte (Initial Value) = " + b);
      System.out.println("short (Initial Value) = " + s);
      System.out.println("int (Initial Value) = " + i);
      System.out.println("long (Initial Value) = " + l);
      System.out.println("float (Initial Value) = " + f);
      System.out.println("double (Initial Value) = " + d);
   }
   public static void main(String[] args) {
      Demo d = new Demo();
      System.out.println("Displaying initial values...");
      d.Display();
   }
}

Output

Displaying initial values...
boolean (Initial Value) = false
byte (Initial Value) = 0
short (Initial Value) = 0
int (Initial Value) = 0
long (Initial Value) = 0
float (Initial Value) = 0.0
double (Initial Value) = 0.0

In the above program, we have declared a variable with different datatypes.

boolean t;
byte b;
short s;
int i;
long l;
float f;
double d;

Now to get the default initial values, just print the variable declared above.

System.out.println("boolean (Initial Value) = " + t);
System.out.println("byte (Initial Value) = " + b);
System.out.println("short (Initial Value) = " + s);
System.out.println("int (Initial Value) = " + i);
System.out.println("long (Initial Value) = " + l);
System.out.println("float (Initial Value) = " + f);
System.out.println("double (Initial Value) = " + d);

The above displays the default values.

raja
Published on 13-Nov-2018 05:17:24
Advertisements