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Demonstrate the concept of pointers using C language
The pointer is a variable that stores the address of another variable.
The syntax for the pointer is as follows −
pointer = &variable;
Example
Following is the C program for the concept of pointers using C language −
#include<stdio.h>
void main(){
//Declaring variables and pointer//
int a=2;
int *p;
//Declaring relation between variable and pointer//
p=&a;
//Printing required example statements//
printf("Size of the integer is %d
",sizeof (int));//4//
printf("Address of %d is %d
",a,p);//Address value//
printf("Value of %d is %d
",a,*p);//2//
printf("Value of next address location of %d is %d
",a,*(p+1));//Garbage value from (p+1) address//
printf("Address of next address location of %d is %d
",a,(p+1));//Address value +4//
//Typecasting the pointer//
//Initializing and declaring character data type//
//a=2 = 00000000 00000000 00000000 00000010//
char *p0;
p0=(char*)p;
//Printing required statements//
printf("Size of the character is %d
",sizeof(char));//1//
printf("Address of %d is %d
",a,p0);//Address Value(p)//
printf("Value of %d is %d
",a,*p0);//First byte of value a - 2//
printf("Value of next address location of %d is %d
",a,*(p0+1));//Second byte of value a - 0//
printf("Address of next address location of %d is %d
",a,(p0+1));//Address value(p)+1//
}Output
When the above program is executed, it produces the following result −
Size of the integer is 4 Address of 2 is 6422028 Value of 2 is 2 Value of next address location of 2 is 463824 Address of next address location of 2 is 6422032 Size of the character is 1 Address of 2 is 6422028 Value of 2 is 2 Value of next address location of 2 is 0 Address of next address location of 2 is 6422029
Updated on: 08-Mar-2021
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