Demonstrate the concept of pointers using C language

The pointer is a variable that stores the address of another variable.

The syntax for the pointer is as follows −

pointer = &variable;

Example

Following is the C program for the concept of pointers using C language −

 Live Demo

#include<stdio.h>
void main(){
   //Declaring variables and pointer//
   int a=2;
   int *p;
   //Declaring relation between variable and pointer//
   p=&a;
   //Printing required example statements//
   printf("Size of the integer is %d
",sizeof (int));//4//
   printf("Address of %d is %d
",a,p);//Address value//
   printf("Value of %d is %d
",a,*p);//2//
   printf("Value of next address location of %d is %d
",a,*(p+1));//Garbage value from (p+1) address//
   printf("Address of next address location of %d is %d
",a,(p+1));//Address value +4//
   //Typecasting the pointer//
   //Initializing and declaring character data type//
   //a=2 = 00000000 00000000 00000000 00000010//
   char *p0;
   p0=(char*)p;
   //Printing required statements//
   printf("Size of the character is %d
",sizeof(char));//1//
   printf("Address of %d is %d
",a,p0);//Address Value(p)//
   printf("Value of %d is %d
",a,*p0);//First byte of value a - 2//
   printf("Value of next address location of %d is %d
",a,*(p0+1));//Second byte of value a - 0//
   printf("Address of next address location of %d is %d
",a,(p0+1));//Address value(p)+1//
}

Output

When the above program is executed, it produces the following result −

Size of the integer is 4
Address of 2 is 6422028
Value of 2 is 2
Value of next address location of 2 is 463824
Address of next address location of 2 is 6422032
Size of the character is 1
Address of 2 is 6422028
Value of 2 is 2
Value of next address location of 2 is 0
Address of next address location of 2 is 6422029