Delete a record with tablename.columnname= value in MySQL

To delete a record in the required way, the syntax is as follows −

delete from yourTableName where yourTableName .yourColumnName=yourValue;

Let us first create a table −

mysql> create table DemoTable
(
   StudentName varchar(100),
   StudentAge int
);
Query OK, 0 rows affected (0.81 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values('Chris',21);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable values('Robert',20);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable values('David',22);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('Mike',24);
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Sam',19);
Query OK, 1 row affected (0.12 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+-------------+------------+
| StudentName | StudentAge |
+-------------+------------+
| Chris       |         21 |
| Robert      |         20 |
| David       |         22 |
| Mike        |         24 |
| Sam         |         19 |
+-------------+------------+
5 rows in set (0.00 sec)

Here’s how you can use tablename.columnname= value to get a value and delete it in MySQL −

mysql> delete from DemoTable where DemoTable.StudentName='Robert';
Query OK, 1 row affected (0.12 sec)

Let us check the table records once again −

mysql> select *from DemoTable;

This will produce the following output −

+-------------+------------+
| StudentName | StudentAge |
+-------------+------------+
| Chris       |         21 |
| David       |         22 |
| Mike        |         24 |
| Sam         |         19 |
+-------------+------------+
4 rows in set (0.00 sec)

AmitDiwan

Updated on: 24-Sep-2019

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