# Delete a Node from linked list without head pointer in C++

In this tutorial, we are going to learn how to delete a node without head pointer in a singly linked list.

Let's see the steps to solve the problem.

• Write struct with data, and next pointer.

• Write a function to insert the node into the singly linked list.

• Initialize the singly linked list with dummy data.

• Take a node from the linked list using the next pointer.

• Move the delete node to the next node.

## Example

Let's see the code.

Live Demo

#include <bits/stdc++.h>
using namespace std;
struct Node {
int data;
struct Node* next;
};
void deleteNodeWithoutHead(struct Node* deletingNode) {
if (deletingNode == NULL) {
return;
}
else {
if (deletingNode->next == NULL) {
cout << "Can't delete last node without head" << endl;
return;
}
struct Node* temp = deletingNode->next;
deletingNode->data = temp->data;
deletingNode->next = temp->next;
free(temp);
}
}
void printLinkedList(Node* head) {
Node* temp = head;
while (temp) {
cout << temp->data << " -> ";
temp = temp->next;
}
}
void insertNode(struct Node** head_ref, int new_data) {
struct Node* new_node = new Node();
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
int main() {
struct Node* head = NULL;
insertNode(&head, 1);
insertNode(&head, 2);
insertNode(&head, 3);
insertNode(&head, 4);
insertNode(&head, 5);
insertNode(&head, 6);
cout << "Linked List before deletion:" << endl;
printLinkedList(head);
Node* del = head->next;
deleteNodeWithoutHead(del);
cout << "\nLinked List after deletion:" << endl;
printLinkedList(head);
return 0;
}

## Output

If you run the above code, then you will get the following result.

Linked List before deletion:
6 -> 5 -> 4 -> 3 -> 2 -> 1 ->
Linked List after deletion:
6 -> 4 -> 3 -> 2 -> 1 ->

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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