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Decimal.Round() Method in C#
The Decimal.Round() method in C# is used to round a value to the nearest integer or specified number of decimal places.
Syntax
Following is the syntax −
public static decimal Round (decimal d); public static decimal Round (decimal d, int decimals); public static decimal Round (decimal d, MidpointRounding mode); public static decimal Round (decimal d, int decimals, MidpointRounding mode);
Example
Let us now see an example to implement the Decimal.Round() method −
using System; public class Demo { public static void Main(){ Decimal val1 = 9.00m; Decimal val2 = 15.29m; Decimal val3 = 394949845.14245M; Console.WriteLine("Decimal 1 = "+val1); Console.WriteLine("Decimal 2 = "+val2); Console.WriteLine("Decimal 2 = "+val2); Console.WriteLine("Remainder = "+(Decimal.Remainder(val1,val2))); Console.WriteLine("Value 1 (Rounded) = "+(Decimal.Round(val1))); Console.WriteLine("Value 2 (Rounded) = "+(Decimal.Round(val2))); Console.WriteLine("Value 3 (Rounded) = "+(Decimal.Round(val3))); } }
Output
This will produce the following output −
Decimal 1 = 9.00 Decimal 2 = 15.29 Decimal 2 = 15.29 Remainder = 9.00 Value 1 (Rounded) = 9 Value 2 (Rounded) = 15 Value 3 (Rounded) = 394949845
Example
Let us now see another example to implement the Decimal.Round() method −
using System; public class Demo { public static void Main(){ Decimal val1 = 6.59m; Decimal val2 = 30.12m; Decimal val3 = 6946649845.25245M; Console.WriteLine("Decimal 1 = "+val1); Console.WriteLine("Decimal 2 = "+val2); Console.WriteLine("Decimal 2 = "+val2); Console.WriteLine("Remainder = "+(Decimal.Remainder(val1,val2))); Console.WriteLine("Value 1 (Rounded) = "+(Decimal.Round(val1,1))); Console.WriteLine("Value 2 (Rounded) = "+(Decimal.Round(val2,1))); Console.WriteLine("Value 3 (Rounded) = "+(Decimal.Round(val3,2))); } }
Output
This will produce the following output −
Decimal 1 = 6.59 Decimal 2 = 30.12 Decimal 2 = 30.12 Remainder = 6.59 Value 1 (Rounded) = 6.6 Value 2 (Rounded) = 30.1 Value 3 (Rounded) = 6946649845.25
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