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DateTime.IsLeapYear() Method in C#
The DateTime.IsLeapYear() method in C# is used to check whether the specified year is a leap year. The return value is a boolean, with TRUE if the year is a leap year, else FALSE.
Syntax
Following is the syntax −
public static bool IsLeapYear (int y);
Above, y is the year to be checked, 2010, 2016, 2019, etc.
Example
Let us now see an example to implement the DateTime.IsLeapYear() method −
using System;
public class Demo {
public static void Main() {
int year = 2019;
Console.WriteLine("Year = "+year);
if (DateTime.IsLeapYear(year)){
Console.WriteLine("Leap Year!");
} else {
Console.WriteLine("Not a Leap Year!");
}
}
}Output
This will produce the following output −
Year = 2019 Not a Leap Year!
Example
Let us now see another example to implement the DateTime.IsLeapYear() method. Here, we will add an out of range year −
using System;
public class Demo {
public static void Main() {
int year = 101910;
Console.WriteLine("Year = "+year);
if (DateTime.IsLeapYear(year)){
Console.WriteLine("Leap Year!");
} else {
Console.WriteLine("Not a Leap Year!");
}
}
}Output
This will produce the following output i.e. error will get generated. The Stack Trace would print the same error as shown below −
Year = 101910 Run-time exception (line 11): Year must be between 1 and 9999. Parameter name: year Stack Trace: [System.ArgumentOutOfRangeException: Year must be between 1 and 9999. Parameter name: year] at System.DateTime.IsLeapYear(Int32 year) at Demo.Main() :line 11
Updated on: 08-Nov-2019
3K+ Views
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