DateTime.IsLeapYear() Method in C#


The DateTime.IsLeapYear() method in C# is used to check whether the specified year is a leap year. The return value is a boolean, with TRUE if the year is a leap year, else FALSE.

Syntax

Following is the syntax −

public static bool IsLeapYear (int y);

Above, y is the year to be checked, 2010, 2016, 2019, etc.

Example

Let us now see an example to implement the DateTime.IsLeapYear() method −

using System;
public class Demo {
   public static void Main() {
      int year = 2019;
      Console.WriteLine("Year = "+year);
      if (DateTime.IsLeapYear(year)){
         Console.WriteLine("Leap Year!");
      } else {
         Console.WriteLine("Not a Leap Year!");
      }
   }
}

Output

This will produce the following output −

Year = 2019
Not a Leap Year!

Example

Let us now see another example to implement the DateTime.IsLeapYear() method. Here, we will add an out of range year −

using System;
public class Demo {
   public static void Main() {
      int year = 101910;
      Console.WriteLine("Year = "+year);
      if (DateTime.IsLeapYear(year)){
         Console.WriteLine("Leap Year!");
      } else {
         Console.WriteLine("Not a Leap Year!");
      }
   }
}

Output

This will produce the following output i.e. error will get generated. The Stack Trace would print the same error as shown below −

Year = 101910
Run-time exception (line 11): Year must be between 1 and 9999.
Parameter name: year
Stack Trace:
[System.ArgumentOutOfRangeException: Year must be between 1 and 9999.
Parameter name: year]
at System.DateTime.IsLeapYear(Int32 year) at Demo.Main() :line 11
raja
Published on 08-Nov-2019 10:41:37
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