# Data Stream as Disjoint Intervals in C++

C++Server Side ProgrammingProgramming

Suppose we have a data stream input of integers, these are like a1, a2, ..., an, ..., we have to summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the input integers are 1, 3, 8, 2, 7, ..., then the summary will be −

• [1,1]

• [1, 1], [3, 3]

• [1, 1], [3, 3], [8, 8]

• [1, 3], [8, 8]

• [1, 3], [7, 8].

To solve this, we will follow these steps −

• Make a set called nums

• in the initializer, set low := -inf and high := inf

• From the addNum method that takes num as input, insert num into the set nums

• From the get interval method, do following −

• Define one 2D array ret

• it := start element of set nums

• while it is in the set, do −

• x := value of it

• if ret is empty or element at index 1 of last element of ret + 1 < x, then,

• insert pair { x, x } at the end of ret

• Otherwise

• increase the element present at index 1 of last element of ret by 1

• it to next element

• return ret

## Example

Let us see the following implementation to get a better understanding −

Live Demo

#include <bits/stdc++.h<
using namespace std;
void print_vector(vector<vector<auto> > v){
cout << "[";
for(int i = 0; i<v.size(); i++){
cout << "[";
for(int j = 0; j <v[i].size(); j++){
cout << v[i][j] << ", ";
}
cout << "],";
}
cout << "]"<<endl;
}
class SummaryRanges {
public:
set <int> nums;
int low, high;
SummaryRanges() {
low = INT_MAX;
high = INT_MIN;
}
nums.insert(val);
}
vector<vector<int>> getIntervals() {
vector < vector <int> > ret;
set <int> :: iterator it = nums.begin();
while(it != nums.end()){
int x = *it;
if(ret.empty() || ret.back()[1] + 1 < x){
ret.push_back({x, x});
} else {
ret.back()[1]++;
}
it++;
}
return ret;
}
};
main(){
SummaryRanges ob;
print_vector(ob.getIntervals());
print_vector(ob.getIntervals());
print_vector(ob.getIntervals());
print_vector(ob.getIntervals());
print_vector(ob.getIntervals());
}

## Input

Initialize the class, then insert one element at a time and see the intervals. So the elements are [1,3,8,2,7]

## Output

[[1, 1, ],]
[[1, 1, ],[3, 3, ],]
[[1, 1, ],[3, 3, ],[8, 8, ],]
[[1, 3, ],[8, 8, ],]
[[1, 3, ],[7, 8, ],]
Published on 27-May-2020 06:16:28