# C++ Program to Perform Uniform Binary Search

In uniform binary search here we implement binary search using a lookup table. It is an improvement in binary search since table lookup is faster than a shift and addition. The time complexity of this approach is O(log(n)).

## Algorithm

Begin
Assign the data to the array in a sorted manner.
Calculate the maximum length of lookup array and declare a new array ‘del’.
Assign the values to the lookup array as n/2, n/4 and so on till ‘0’, where n is the length of the data
array.
Call UniBinarySearch() function.
Assign mid to the value at ‘0’ index of ‘dl’ array and compare key to the value at mid index.
If key is equal then return the index value to the main.
If index value in ‘dal’ is zero then the element is not there, return - 1 to main.
If it is lesser, subtract next value stored in ‘dal’ array and shift the pointer to next value in ‘dal’
array.
If it is greater, add next value stored in ‘dal’ array and shift the pointer to next value in ‘dal’ array.
print the index value returned by the function and ask for user’s choice to search more.
End

## Example Code

#include<iostream>
using namespace std;
void lookUpArray(int *a, int N) {
int power = 1, i = 0;
do {
int half = power;
power *= 2;
a[i] = (N+half)/power;
i++;
} while (a[i-1] != 0);
}
int UniBinarySearch(int *a, int *dal, int key) {
int i = d-1, d = 0;
flag:
if (key == a[i])
return i;
else if (dal[d] == 0)
return -1;
else {
if (key < a[i]) {
i -= dal[++d];
goto flag;
}
else {
i += dal[++d];
goto flag;
}
}
}
int main(void) {
int i, n = 10, d = 0, pow = 1, index;
char ch;
int a = {2,6,7, 10, 12, 14, 12, 16,20, 26};
while(pow <= n) {
pow *=2;
d++;
}
int del[d];
lookUpArray(d, n);
up:
cout<<"\nEnter the Element to be searched: ";
cin>>n;
index = UniBinarySearch(a, del, n);
if (index == -1)
else
cout<<"\nItem "<<n<<" found at "<<index+1<<" position";
cout<<"\n\n\tDo you want to search more...enter choice(y/n)?";
cin>>ch;
if(ch == 'y' || ch == 'Y')
goto up;
return 0;
}

## Output

Enter the Element to be searched: 7
Item 7 found at 3 position
Do you want to search more...enter choice(y/n)?y
Enter the Element to be searched: 21
Do you want to search more...enter choice(y/n)?