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C++ Program to Perform Edge Coloring of a Graph
In this program, we will perform Edge Coloring of a Graph in which we have to color the edges of the graph that no two adjacent edges have the same color. Steps in Example.
Algorithm
Begin Take the input of the number of vertices, n, and then number of edges, e, in the graph. The graph is stored as adjacency list. BFS is implemented using queue and colors are assigned to each edge. End
Example
#include<bits/stdc++.h>
using namespace std;
int n, e, i, j;
vector<vector<pair<int, int> > > g;
vector<int> color;
bool v[111001];
void col(int n) {
queue<int> q;
int c = 0;
set<int> vertex_colored;
if(v[n])
return;
v[n] = 1;
for(i = 0;i<g[n].size();i++) {
if(color[g[n][i].second]!=-1) {
vertex_colored.insert(color[g[n][i].second]);
}
}
for(i = 0;i<g[n].size();i++) {
if(!v[g[n][i].first]) {
q.push(g[n][i].first);
}
if(color[g[n][i].second]==-1) {
while(vertex_colored.find(c)!=vertex_colored.end())
c++;
color[g[n][i].second] = c;
vertex_colored.insert(c);
c++;
}
}
while(!q.empty()) {
int temp = q.front();
q.pop();
col(temp);
}
return;
}
int main() {
int u,w;
set<int> empty;
cout<<"Enter number of vertices and edges respectively:";
cin>>n>>e;
cout<<"\n";
g.resize(n); //number of vertices
color.resize(e,-1); //number of edges
memset(v,0,sizeof(v));
for(i = 0;i<e;i++) {
cout<<"\nEnter edge vertices of edge "<<i+1<<" :"<<"\n";
cin>>u>>w;
u--; w--;
g[u].push_back(make_pair(w,i));
g[w].push_back(make_pair(u,i));
}
col(0);
for(i = 0;i<e;i++) {
cout<<"Edge "<<i+1<<" is coloured with colour "<<color[i]+1
<< "\n";
}
}Output
Enter number of vertices and edges respectively:4 5 Enter edge vertices of edge 1 :1 2 Enter edge vertices of edge 2 :2 3 Enter edge vertices of edge 3 :1 1 Enter edge vertices of edge 4 :3 4 Enter edge vertices of edge 5 :1 4 Edge 1 is coloured with colour 1 Edge 2 is coloured with colour 2 Edge 3 is coloured with colour 2 Edge 4 is coloured with colour 1 Edge 5 is coloured with colour 3
Updated on: 30-Jul-2019
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