# C++ Program to Generate N Number of Passwords of Length M Each

C++Server Side ProgrammingProgramming

This is a C++ Program to Generate N Number of Passwords of Length M Each.

## Algorithm

Begin
Take the length of password as input.
/* Arguments
A pointer array a.
Total Number of random numbers m.
*/
// Body of the function:
if (m == s)
for i = 0 to s-1
Print *(a + i)
else
for i = m to s-1
int tmp = a[m]
a[m] = a[i]
a[i] = tmp
Call permutation(a, m + 1, s)
tmp = a[m]
a[m] = a[i]
a[i] = tmp
End

## Example

#include<iostream>
#include<conio.h>
#include<stdlib.h>
using namespace std;
void permutation(int *a, int m, int s) {
if (m == s) {
for (int i = 0; i < s; i++) {
cout << *(a + i);
}
cout << endl;
} else {
for (int i = m; i < s; i++) {
int tmp = a[m];
a[m] = a[i];
a[i] = tmp;
permutation(a, m + 1, s);
tmp = a[m];
a[m] = a[i];
a[i] = tmp;
}
}
}
int main(int argc, char **argv) {
cout << "Enter the length of the password: ";
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
a[i] = rand() % 10; //randomly generate numbers
}
cout <<"Random Numbers are:" <<endl;
for (int i = 0; i < n; i++) {
cout<<a[i] <<endl;
}
cout << "The Passwords are: "<<endl;
permutation(a, 0, n);
}

## Output

Enter the length of the password: 4
Random Numbers are:
1740T
1740
1704
1470
1407
1047
1074
7140
7104
7410
7401
7041
7014
4710
4701
4170
4107
4017
4071
0741
0714
0471
0417
0147
0174
Published on 30-Apr-2019 09:00:32