C++ program to find ΔX which is added to numerator and denominator both of fraction (a/b) to convert it to another fraction (c/d)

Server Side ProgrammingProgramming

Beyond Basic Programming - Intermediate Python

Most Popular

36 Lectures 3 hours

C Programming from scratch- Master C Programming

Best Seller

60 Lectures 8 hours

C++ Programming

238 Lectures 56.5 hours

In this article, we will be discussing a program to find ΔX which is added to the numerator and denominator both of given fraction (a/b) to convert it to another given irreducible fraction (c/d).

For example, let us suppose we have been given with the following values,

a = 4 | b = 2 | c = 4 | d = 3

then ΔX would be 4 such that (a + ΔX)/(b + ΔX) = 8/6 = 2/3

As we know, (a + ΔX)/(b + ΔX) = c/d. Solving this equation for ΔX, we get

ΔX = (bc - ad) / (d - c)

Example

Live Demo

#include <iostream>
using namespace std;
int main() {
int a = 4;
int b = 2;
int c = 4;
int d = 3;
int dif = 0;
dif = (b*c-a*d)/(d-c);
cout << "The value of \u0394x :" << endl;
cout << dif << endl;
return 0;
}

Output

The value of Δx :
4
Updated on 03-Oct-2019 12:30:47