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C++ program to find the sum of the series (1/a + 2/a^2 + 3/a^3 + … + n/a^n)
In this tutorial, we will be discussing a program to find the sum of the given series (1/a + 2/a^2 + 3/a^3 + … + n/a^n).
For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.
Example
#include <iostream>
#include <math.h>
using namespace std;
//calculating the sum of the series
float calc_sum(int a, int n) {
int i;
float sum = 0;
for (i = 1; i <= n; i++)
sum += (i/ pow(a, i));
return sum;
}
int main() {
int a = 3, n = 4;
float res = calc_sum(a,n);
cout << res << endl;
return 0;
}Output
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Updated on: 09-Jul-2020
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