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In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1,5, 32, 288 ...

**Let’s take an example to understand the problem,**

N = 4

288

4^{th} term − (4^4) + (3^3) + (2^2) + (1^1) = 256 + 27 + 4 + 1 = 288

A simple approach to solve the problem is by using the general formula for the nth term of the series. The formula for,

Nth term = ( N^N ) + ( (N-1)^(N-1) ) + … + ( 2^2 ) + ( 1^1 )

**Program to illustrate the working of our solution,**

#include <iostream> using namespace std; int calcNthTerm(int N) { if (N <= 1) return 1; int factorial = 1; for (int i = 1; i < N; i++) factorial *= i; return factorial; } int main() { int N = 8; cout<<N<<"th term of the series is "<<calcNthTerm(N); return 0; }

8th term of the series is 5040

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