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C++ program to find minimum how much rupees we have to pay to buy exactly n liters of water
Suppose we have three numbers n, a and b. We want to buy n liters of water. There are only two types of water bottles nearby, 1-liter bottles and 2-liter bottles. The bottle of the first type a rupees and the bottle of the second type costs b rupees. We want to spend as few money as possible. We have to find the minimum amount of money we need to buy exactly n liters of water.
So, if the input is like n = 7; a = 3; b = 2, then the output will be 9, because with 3 2-liter bottles we can get 6 liters of water with price 6, then one 1 liter bottle is needed for cost 3.
Steps
To solve this, we will follow these steps −
b := minimum of a * 2 and b return (n / 2 * b) + (n mod 2) * a
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int solve(int n, int a, int b) {
b = min(a * 2, b);
return n / 2 * b + n % 2 * a;
}
int main() {
int n = 7;
int a = 3;
int b = 2;
cout << solve(n, a, b) << endl;
}Input
7, 3, 2
Output
9
Updated on: 04-Mar-2022
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