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C++ Program to Compute Cross Product of Two Vectors
This is a C++ program to compute Cross Product of Two Vectors.
Let us suppose,
M = m1 * i + m2 * j + m3 * k
N = n1 * i + n2 * j + n3 * k.
So, cross product = (m2 * n3 – m3 * n2) * i + (m1 * n3 – m3 * n1) * j + (m1 * n1 – m2 * n1) * k
where m2 * n3 – m3 * n2, m1 * n3 – m3 * n1 and m1 * n1 – m2 * n1 are the coefficients of unit vector along i, j and k directions.
Algorithm
Begin Declare a function cProduct(). Declare three vectors v_A[], v_B[], c_P[] of the integer datatype. c_P[0] = v_A[1] * v_B[2] - v_A[2] * v_B[1]. c_P[1] = -(v_A[0] * v_B[2] - v_A[2] * v_B[0]). c_P[2] = v_A[0] * v_B[1] - v_A[1] * v_B[0]. Initialize values in v_A[] vector. Initialize values in v_B[] vector. Initialize c_P[] vector with an integer variable n. Print “Cross product:”. Call the function cProduct() to perform cross product within v_A[] and v_B[]. for (int i = 0; i < n; i++) print the value of c_P[] vector. End.
Example Code
#include
#define n 3
using namespace std;
void crossProduct(int v_A[], int v_B[], int c_P[]) {
c_P[0] = v_A[1] * v_B[2] - v_A[2] * v_B[1];
c_P[1] = -(v_A[0] * v_B[2] - v_A[2] * v_B[0]);
c_P[2] = v_A[0] * v_B[1] - v_A[1] * v_B[0];
}
int main() {
int v_A[] = { 7, 6, 4 };
int v_B[] = { 2, 1, 3 };
int c_P[n];
cout << "Cross product:";
crossProduct(v_A, v_B, c_P);
for (int i = 0; i < n; i++)
cout << c_P[i] << " ";
return 0;
}Output
Cross product: 14 13 -5
Updated on: 26-Feb-2020
6K+ Views
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