# C++ program to check we can rearrange array in such a way that given formula returns m or not

C++Server Side ProgrammingProgramming

#### C in Depth: The Complete C Programming Guide for Beginners

45 Lectures 4.5 hours

#### Practical C++: Learn C++ Basics Step by Step

Most Popular

50 Lectures 4.5 hours

#### Master C and Embedded C Programming- Learn as you go

66 Lectures 5.5 hours

Suppose we have an array A with n elements and another number m. We have to check whether we can rearrange the array in such a way that

$$\mathrm{\sum_{i=1}^{n} \sum_{j=1}^{n}\frac{A[j]}{j} = m}$$

There will be no rounding in A[j]/j operation.

So, if the input is like A = [2, 5, 1]; m = 8, then the output will be True, because for the arrangement of [1, 2, 5], (1/1 + 2/2 + 5/3) + (2/2 + 5/3) + (5/3) = 8

## steps

To solve this, we will follow these steps −

sum := 0
n := size of A
for initialize i := 0, when i < n, update (increase i by 1), do:
sum := sum + A[i]
if sum is same as m, then:
return true
Otherwise
return false

## Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h>
using namespace std;

bool solve(vector<int> A, int m) {
long sum = 0;
int n = A.size();
for (int i = 0; i < n; ++i) {
sum += A[i];
}
if (sum == m)
return true;
else
return false;
}

int main() {
vector<int> A = { 2, 5, 1 };
int m = 8;
cout << solve(A, m) << endl;
}

## Input

{ 2, 5, 1 }, 8

## Output

1