# C++ Program to check joke programming code is generating output or not

Suppose we have a string S with n characters. In a joke programming language, there are only 4 instructions.

• "H" to print "Hello World"
• "Q" to print its source code
• "9" to print "99 bottles of juice"
• "+" to increment the value stored in accumulator

Instructions "H" and "Q" are case-sensitive and they must be in uppercase. The characters except these four are ignored. We have a program written in this language. You have to check whether executing this program will produce any output or not.

## Problem Category

Various problems in programming can be solved through different techniques. To solve a problem, we have to devise an algorithm first, and to do that we have to study the particular problem in detail. A recursive approach can be used if there is a recurring appearance of the same problem over and over again; alternatively, we can use iterative structures also. Control statements such as if-else and switch cases can be used to control the flow of logic in the program. Efficient usage of variables and data structures provides an easier solution and a lightweight, low-memory-requiring program. We have to look at the existing programming techniques, such as Divide-and-conquer, Greedy Programming, Dynamic Programming, and find out if they can be used. This problem can be solved by some basic logic or a brute-force approach. Follow the following contents to understand the approach better.

So, if the input of our problem is like S = "H+995jkl", then the output will be True, because H, + and 9 are valid instructions.

## Steps

To solve this, we will follow these steps −

for initialize i := 0, when i < size of S, update (increase i by 1), do:
c := S[i]
if c is same as 'H' or c is same as 'Q' or c is same as '9', then:
return true
return false

## Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h>
using namespace std;
bool solve(string S){
for (int i = 0; i < S.size(); i++){
char c = S[i];
if (c == 'H' || c == 'Q' || c == '9'){
return true;
}
}
return false;
}
int main(){
string S = "H+995jkl";
cout << solve(S) << endl;
}

## Input

"H+995jkl"

## Output

1

Updated on: 08-Apr-2022

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