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C++ Program for triangular pattern (mirror image around 0)
Given with the positive value n and the task is to generate the triangular pattern i.e. mirror image of the printed numbers and display the result
Example
Input-: n = 6 Output-:
Input-: n = 3 Output-:
Approach used in the below program is as follows −
- Input the value of n as a positive integer
- Traverse one loop i for the number of rows in a pattern i.e. n
- Traverse one loop j for the number of spaces in a pattern
- Traverse another loop for the digits in a pattern
Algorithm
START Step 1-> declare function to print mirror image of triangular pattern void print_mirror(int n) declare and set int temp = 1 and temp2 = 1 Loop for int i = 0 and i < n and i++ Loop For int j = n - 1 and j > i and j— print space End Loop For int k = 1 and k <= temp and k++ print abs(k - temp2) End Set temp += 2 increment temp2++ print \n Step 2-> In main() Declare int n = 6 print_mirror(n) STOP
Example
#include <bits/stdc++.h>
using namespace std;
//function to print mirror image of triangular pattern
void print_mirror(int n) {
int temp = 1, temp2 = 1;
for (int i = 0; i < n; i++) {
for (int j = n - 1; j > i; j--) {
cout << " ";
}
for (int k = 1; k <= temp; k++) {
cout << abs(k - temp2);
}
temp += 2;
temp2++;
cout << "\n";
}
}
int main() {
int n = 6;
print_mirror(n);
return 0;
}Output
Updated on: 09-Jul-2020
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