Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
C++ code to find how long person will alive between presses
Suppose we have four numbers d, L, v1 and v2. Two presses are initially at location 0 and L, they are moving towards each other with speed v1 and v2 each. The width of a person is d, he dies if the gap between two presses is less than d. We have to find how long the person will stay alive.
So, if the input is like d = 1; L = 9; v1 = 1; v2 = 2;, then the output will be 2.6667
Steps
To solve this, we will follow these steps −
e := (L - d)/(v1 + v2) return e
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
float solve(int d, int L, int v1, int v2){
float e = (L - d) / (float)(v1 + v2);
return e;
}
int main(){
int d = 1;
int L = 9;
int v1 = 1;
int v2 = 2;
cout << solve(d, L, v1, v2) << endl;
}Input
1, 9, 1, 2
Output
2.66667
Updated on: 30-Mar-2022
69 Views
Advertisements