C++ code to find answers by vowel checking

Suppose we have a string S. Amal and Bimal are playing a game. The rules of the game are like: Those who play for the first time, that is Amal is the detective, he should investigate a "crime" and find out the cause. He can ask any questions whose answers will be either "Yes" or "No". If the question’s last letter is a vowel, they answer "Yes" otherwise "No". Here the vowels are: A, E, I, O, U, Y. We have S as question and we have to find the answer.

So, if the input is like S = "Is it in university?", then the output will be Yes.

Steps

To solve this, we will follow these steps −

s := "AEIOUYaeiouy"
for initialize i := 0, when i < size of S, update (increase i by 1),
do:
   t := S[i]
   if t is alphabetic, then:
      ans := t
if ans is in s, then:
   return "YES"
Otherwise
   return "NO"

Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h>
using namespace std;
string solve(string S){
   string s = "AEIOUYaeiouy";
   char ans;
   for (int i = 0; i < S.size(); i++){
      char t = S[i];
      if (isalpha(t))
         ans = t;
   }
   if (s.find(ans) != -1)
      return "YES";
   else
      return "NO";
}
int main(){
   string S = "Is it in university?";
   cout << solve(S) << endl;
}