C++ code to count days to complete reading book

Suppose we have an array A with n elements and have another value t. On ith day Amal spends A[i] seconds in work. In the free time he reads a book. The entire book will take t seconds to complete. We have to find how many days he will need to read the complete book.

So, if the input is like A = [86400, 86398]; t = 2, then the output will be 2, because one day has 86400 seconds, and first day is totally blocked. On second day he will get 2 seconds to complete the book.

Steps

To solve this, we will follow these steps −

cnt := 1
n := size of A
for initialize i := 0, when i 
Example
Let us see the following implementation to get better understanding −
#include 
using namespace std;
int solve(vector A, int t){
   int cnt = 1;
   int n = A.size();
   for (int i = 0; i  A = { 86400, 86398 };
   int t = 2;
   cout 
Input
{ 86400, 86398 }, 2
Output
2