Count the number of pairs (i, j) such that either arr[i] is divisible by arr[j] or arr[j] is divisible by arr[i] in C++

We are given with an array arr[] of N elements. The goal is to find the count of all valid pairs of indexes (i,j) such that either arr[i] is divisible by arr[j] or arr[j] is divisible by arr[i] and i!=j.

We will do this by traversing the array arr[] using two for loops for each number of pair and check if arr[i]%arr[j]==0 or arr[j]%arr[i]==0 when i!=j. If true increment count of pairs.

Let’s understand with examples.

Input − Arr[]= { 2,4,3,6 } N=4

Output − Count of valid pairs − 3

Explanation − Valid pairs are −

Arr[0] & Arr[1] → (2,4) here 4%2==0 0!=1
Arr[0] & Arr[1] → (2,6) here 6%2==0 0!=3
Arr[2] & Arr[3] → (3,6) here 6%3==0 2!=3

Input − Arr[]= { 2,5,7,9,11 } N=5

Output− Count of valid pairs − 0

Explanation − No number fully divides the other. No pair can be formed.

Approach used in the below program is as follows

  • We take an integer array Arr[] initialized with random numbers.

  • Take a variable n which stores the length of Arr[].

  • Function countPairs(int arr[], int n) takes an array, its length as input and returns the pairs which are valid and meet desired conditions.

  • Traverse array using two for loops for each element of the pair.

  • Outer Loop from 0<=i<n-1, inner loop i<j<n

  • Check if arr[i]%arr[j]==0 or arr[j]%arr[i]==0. Increment count once if either of condition is true.

  • At the end of all loops count will have a total number of pairs that are valid

  • Return the count as result.


 Live Demo

#include <bits/stdc++.h>
using namespace std;
int countPairs(int arr[], int n){
   // Count of pairs
   int count = 0;
   for (int i = 0; i < n-1; i++){
      for (int j = i + 1; j < n; j++){
         if(arr[i]%arr[j]==0 || arr[j]%arr[i]==0)
            { count++; }
   return count;
int main(){
   int Arr[] = { 2,3,4,5,6 };
   int len = sizeof(Arr) / sizeof(Arr[0]);
   cout << "Count of number of pairs : "<< countPairs(Arr, len);
   return 0;


If we run the above code it will generate the following output −

Count of number of pairs : 3

Updated on: 29-Aug-2020


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