# Count of pairs from 1 to a and 1 to b whose sum is divisible by N in C++

C++Server Side ProgrammingProgramming

We are given an integer array and the task is to count the total number of pairs (x, y) that can be formed using the given array values such that the integer value of x is less than y.

Input − int a = 2, b = 3, n = 2

Output − Count of pairs from 1 to a and 1 to b whose sum is divisible by N are − 3

Explanation

Firstly, We will start from 1 to a which includes 1, 2
Now, we will start from 1 to b which includes 1, 2, 3
So the pairs that can be formed are (1,1), (1,2), (1, 3), (2, 1), (2, 2), (2, 3) and their respective
sum are 2, 3, 4, 3, 4, 5. The numbers 2, 4, 4 are divisible by the given N i.e. 2. So the count is 3.

Input − int a = 4, b = 3, n = 2

Output − Count of pairs from 1 to a and 1 to b whose sum is divisible by N are − 3

Explanation

Firstly, We will start from 1 to a which includes 1, 2, 3, 4
Now, we will start from 1 to b which includes 1, 2, 3
So the pairs that can be formed are (1,1), (1,2), (1, 3), (2, 1), (2, 2), (2, 3), (3,1), (3, 2), (3, 3), (4,
1), (4, 2), (4, 3) and their respective sum are 2, 3, 4, 3, 4, 5, 4, 5, 6, 5, 6, 7. The numbers 3, 3, 6,
6 are divisible by the given N i.e. 3. So the count is 4

## Approach used in the below program is as follows

• Input integer variables a, b and n for 1 to a, 1 to b and divisibility comparison with n

• Pass all the data to the function for further processing

• Create a temporary variable count to store the pairs

• Start loop FOR from i to 0 till a

• Inside the loop, start another loop FOR from j to 0 till b

• Inside the loop, set sum with i + j

• Inside the loop, check IF sum % n == 0 then increment the count by 1

• Return the count

• Print the result

## Example

Live Demo

#include <iostream>
using namespace std;
int Pair_a_b(int a, int b, int n){
int count = 0;
for (int i = 1; i <= a; i++){
for (int j = 1; j <= b; j++){
int temp = i + j;
if (temp%n==0){
count++;
}
}
}
return count;
}
int main(){
int a = 2, b = 20, n = 4;
cout<<"Count of pairs from 1 to a and 1 to b whose sum is divisible by N are: "<<Pair_a_b(a, b, n);
return 0;
}

## Output

If we run the above code it will generate the following output −

Count of pairs from 1 to a and 1 to b whose sum is divisible by N are: 10
Updated on 31-Aug-2020 11:24:22