Count of lines required to write the given String in C++

C++Server Side ProgrammingProgramming

We are given a string Str of alphabets and an array widths[]containing width of all English alphabets. The goal is to find the number of lines required to print this string on a page which has a width of 10 characters. Also print remaining characters.

We will traverse the string check width of the current character and add it, if this sum >=10 increment number of lines.

Let’s understand with examples.

Input 

Str = "ababababab"
widths[] = {2, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,1, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 1, 1};

Output 

Count of lines: 2 Remaining width: 6

Explanation 

line 1 : ababab ( 2+1+2+1+2+1 = 3+3+3=9)
line 2 : abab (2+1+2+1)

Input 

Str = "bbbbbbbbbbdd"
widths[] = {2, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,1, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 1, 1};

Output 

Count of lines: 2 Remaining width: 2

Explanation 

line 1 : bbbbbbbbbb (1+1+1+1+1+1+1+1+1+1=10)
line 2 : dd (1+1)

Approach used in the below program is as follows

  • We have a string Str and array widths[] of space of each alphabet.

  • Function numberOfLines(string str,int len, int w[]) displays number of lines in page and width of characters in the last line.

  • Take initial count of lines as numoflines=0.

  • Take initial last line width as remain=0

  • Traverse string str using for loop.

  • Take current character c as str[i].

  • Check width of c as num=width[c-’a’].

  • Add this num to remain.

  • If remain >=10 increment line count and update remain as num.

  • Print results at the end of for loop.

Example

 Live Demo

#include <bits/stdc++.h>
using namespace std;
// Function to return the number of lines required
void numberOfLines(string str,int len, int w[]){
   int numoflines = 0;
   int remain = 0;
   //traversing string
   for (int i=0;i<len;i++){
      char c=str[i]; //current character
      int num = w[c - 'a']; //units for current character remain += num;
      if (remain >= 10){
         numoflines+=1;
         remain = num;
      }
   }
   cout<<"Count of lines: "<<numoflines;
   cout<<endl<<"Remaining width: "<<remain;
}
int main(){
   string Str = "abcdefghijklmnop";
   int length=Str.length();
   int widths[] = {2, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 1, 1};
   numberOfLines(Str,length,widths);
   return 0;
}

Output

If we run the above code it will generate the following output −

Count of lines: 3
Remaining width: 1
raja
Published on 31-Oct-2020 05:46:45
Advertisements