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# Count Odd and Even numbers in a range from L to R in C++

We are given a range starting from L to R of integer values and the task is to calculate the count of odd numbers and the even numbers in the range.

**Input** − L = 7, R = 17

**Output** − Count of Even numbers in a range from L to R are − 5

Count of Odd numbers in a range from L to R are − 6

**Input** − L = 1, R = 10

**Output** − Count of Even numbers in a range from L to R are − 5

Count of Odd numbers in a range from L to R are − 5

## Approach used in the below program is as follows

Input the range starting from L to R

Pass the L and R values to the function to find out the even values and then we will calculate the odd values depending upon the return value.

Start loop FOR from i to L till R

Inside the loop, check IF i%2==0 then increment the even count by 1

Return the even count

Now to calculate the odd count set odd as (R - L + 1) - even

## Example

#include <iostream> using namespace std; int Odd_Even(int L, int R){ int even = 0; for(int i = L ;i < R ;i++){ if(i%2==0){ even++; } } return even; } int main(){ int L = 7, R = 17; int even = Odd_Even(L, R); int odd = (R - L + 1) - even; cout<<"Count of Even numbers in a range from L to R are: "<<even<<endl; cout<<"Count of Odd numbers in a range from L to R are: "<<odd; return 0; }

## Output

If we run the above code it will generate the following output −

Count of Even numbers in a range from L to R are: 5 Count of Odd numbers in a range from L to R are: 6

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