- Related Questions & Answers
- Count of all N digit numbers such that num + Rev(num) = 10^N - 1 in C++
- Count n digit numbers not having a particular digit in C++
- Count numbers having 0 as a digit in C++
- Count all possible N digit numbers that satisfy the given condition in C++
- Count divisors of n that have at-least one digit common with n in Java
- Find count of Almost Prime numbers from 1 to N in C++
- Count n digit numbers divisible by given number in C++
- Count of Binary Digit numbers smaller than N in C++
- Count of different ways to express N as the sum of 1, 3 and 4 in C++
- Count the numbers < N which have equal number of divisors as K in C++
- Program to find duplicate element from n+1 numbers ranging from 1 to n in Python
- Count total number of digits from 1 to N in C++
- Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++\n
- Count pairs of numbers from 1 to N with Product divisible by their Sum in C++
- Maximum XOR using K numbers from 1 to n in C++

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

In this tutorial, we will be discussing a program to find the numbers from 1 to n that have 4 as a digit.

For this we will be provided with a number n. Our task is to count all the numbers which have 4 as one of their digits and print it out.

#include<iostream> using namespace std; bool has4(int x); //returning sum of digits in the given numbers int get_4(int n){ int result = 0; //calculating the sum of each digit for (int x=1; x<=n; x++) result += has4(x)? 1 : 0; return result; } //checking if 4 is present as a digit bool has4(int x) { while (x != 0) { if (x%10 == 4) return true; x = x /10; } return false; } int main(){ int n = 328; cout << "Count of numbers from 1 to " << n << " that have 4 as a digit is " << get_4(n) << endl; return 0; }

Count of numbers from 1 to 328 that have 4 as a digit is 60

Advertisements