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# Count numbers from 1 to n that have 4 as a digit in C++

In this tutorial, we will be discussing a program to find the numbers from 1 to n that have 4 as a digit.

For this we will be provided with a number n. Our task is to count all the numbers which have 4 as one of their digits and print it out.

## Example

#include<iostream> using namespace std; bool has4(int x); //returning sum of digits in the given numbers int get_4(int n){ int result = 0; //calculating the sum of each digit for (int x=1; x<=n; x++) result += has4(x)? 1 : 0; return result; } //checking if 4 is present as a digit bool has4(int x) { while (x != 0) { if (x%10 == 4) return true; x = x /10; } return false; } int main(){ int n = 328; cout << "Count of numbers from 1 to " << n << " that have 4 as a digit is " << get_4(n) << endl; return 0; }

## Output

Count of numbers from 1 to 328 that have 4 as a digit is 60

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