Count number of bits changed after adding 1 to given N in C++

We are given a number let’s say num and the task is to calculate the total number of bits changed when 1 is added to a number.

Binary representation of a number is done by converting the given number into the form of 0’s and 1’s and it is done by various methods. In one method, we calculate the LCM of a given number by 2 and if a reminder is other than 0 then the bit is set to 1 else it will be set to 0.

Addition table for bits are

0 + 1 = 1
1 + 0 = 1
0 + 0 = 0
1 + 1 = 1 ( 1 bit carry)

For Example

Input − num = 10
Output − count is : 1

Explanation − binary representation of 10 is 1010 and when 1 is added to it representation becomes 1011. Clearly only one bit got changed therefore the count is 1.

Input − num = 5
Output − count is : 2

Explanation − binary representation of 5 is 101 and when 1 is added to it representation becomes 110. Clearly two bits got changed therefore the count is 2

Approach used in the below program is as follows

Input the number of type integer let’s say, int num
Declare a variable that will store the count let’s say, int count
Take another variable let’s say temp that will calculate the XOR of num and set it to n ^ (n + 1)
In the count variable call __builtin_popcount(temp). This function is to calculate the count of numbers in a given integer binary representation. It is an inbuilt function of GCC compiler.
Return the count
Print the result.

Example

Live Demo

#include <iostream>
using namespace std;
// Function to find number of changed bit
int changedbit(int n){
   int XOR = n ^ (n + 1);
   // Count set bits in xor value
   int count = __builtin_popcount(XOR);
   return count;
}
int main(){
   int n = 10;
   cout <<"count is: " <<changedbit(n);
   return 0;
}