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Count groups of negatives numbers in JavaScript
We have an array of numbers like this −
const arr = [-1,-2,-1,0,-1,-2,-1,-2,-1,0,1,0];
Let’s say, we are required to write a JavaScript function that counts the consecutive groups of negative numbers in the array.
Like here we have consecutive negatives from index 0 to 2 which forms one group and then from 4 to 8 forms the second group
So, for this array, the function should return 2.
Example
Let’s write the code −
const arr = [-1,-2,-1,0,-1,-2,-1,-2,-1,0,1,0];
const countNegativeGroup = arr => {
return arr.reduce((acc, val, ind) => {
if(val < 0 && arr[ind+1] >= 0){
acc++;
};
return acc;
}, 0);
};
console.log(countNegativeGroup(arr));Output
Following is the output in the console −
2
Updated on: 14-Sep-2020
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