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Convert to number with digits as 3 and 8 only in C++
In this tutorial, we will be discussing a program to convert a number to have digits as 3 and 8 only.
For this we will be provided with a random number. Our task is to convert its digits to be only 3 and 8 by either adding/subtracting 1 from the number or converting digits of the number to any desired digit.
Example
#include <bits/stdc++.h> using namespace std; //calculating minimum operations required int cal_min(long long int num){ //calculating remainder and operations int rem; int count = 0; while (num) { rem = num % 10; if (!(rem == 3 || rem == 8)) count++; num /= 10; } return count; } int main(){ long long int num = 2341974; cout << "Minimum Operations: " << cal_min(num); return 0; }
Output
Minimum Operations: 6
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