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Convert singly linked list into XOR linked list in C++
In this tutorial, we will be discussing a program to convert a singly linked list into XOR linked list.
For this we will be provided with a singly linked list. Our task is to take the elements of that list and get it converted into a XOR linked list.
Example
#include <bits/stdc++.h>
using namespace std;
//node structure of linked list
struct Node {
int data;
struct Node* next;
};
//creation of new node
Node* newNode(int data){
Node* temp = new Node;
temp->data = data;
temp->next = NULL;
return temp;
}
//printing singly linked list
void print(Node* head){
while (head) {
cout << head->data << " ";
head = head->next;
}
cout << endl;
}
//calculating XORed values
Node* XOR(Node* a, Node* b){
return (Node*)((uintptr_t)(a) ^ (uintptr_t)(b));
}
//converting the singly linked list
void convert(Node* head){
Node* curr = head;
Node* prev = NULL;
Node* next = curr->next;
while (curr) {
next = curr->next;
curr->next = XOR(prev, next);
prev = curr;
curr = next;
}
}
//printing the XORed linked list
void printXOR(Node* head){
Node* curr = head;
Node* prev = NULL;
while (curr) {
cout << curr->data << " ";
Node* temp = curr;
curr = XOR(prev, curr->next);
prev = temp;
}
cout << endl;
}
int main(){
Node* head = newNode(1);
head->next = newNode(2);
head->next->next = newNode(3);
head->next->next->next = newNode(4);
cout << "Before Conversion : " << endl;
print(head);
convert(head);
cout << "After Conversion : " << endl;
printXOR(head);
return 0;
}Output
Before Conversion : 1 2 3 4 After Conversion : 1 2 3 4
Updated on: 22-Jan-2020
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