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Convert all substrings of length ‘k’ from base ‘b’ to decimal in C++
In this tutorial, we will be discussing a program to convert all substrings of length ‘k’ from base ‘b’ to decimal.
For this we will be provided with a string of some certain length. Our task is to take the substrings from the given string of size ‘k’ and get it converted into the decimal numbers from being in base ‘b’.
Example
#include <bits/stdc++.h>
using namespace std;
//converting the substrings to decimals
int convert_substrings(string str, int k, int b){
for (int i=0; i + k <= str.size(); i++){
//getting the substring
string sub = str.substr(i, k);
//calculating the decimal equivalent
int sum = 0, counter = 0;
for (int i = sub.size() - 1; i >= 0; i--){
sum = sum + ((sub.at(i) - '0') * pow(b, counter));
counter++;
}
cout << sum << " ";
}
}
int main(){
string str = "12212";
int b = 3, k = 3;
convert_substrings(str, b, k);
return 0;
}Output
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Updated on: 16-Jan-2020
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