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Consecutive Numbers Sum in C++
Suppose we have a positive integer N, we have to find how many different ways can we write it as a sum of consecutive positive integers?
So, if the input is like 10, then the output will be 3, this is because we can represent 10 as 5 + 5 and 7 + 3, so there are two different ways.
To solve this, we will follow these steps −
ret := 1
for initialize i := 2, (increase i by 1), do −
sum := (i * (i + 1)) / 2
if sum > N, then −
Come out from the loop
rem := N - sum
ret := ret + (1 when rem mod i is 0, otherwise 0)
return ret
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
int consecutiveNumbersSum(int N) {
int ret = 1;
for(int i = 2; ; i++){
int sum = (i * (i + 1)) / 2;
if(sum > N) break;
int rem = N - sum; ret += (rem % i == 0);
}
return ret;
}
}; main(){
Solution ob;cout << (ob.consecutiveNumbersSum(10));
}Input
10
Output
2
Updated on: 04-Jun-2020
867 Views
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