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Compare two file paths in Java
Two file paths can be compared lexicographically in Java using the method java.io.File.compareTo(). This method requires a single parameter i.e.the abstract path name that is to be compared. It returns 0 if the two file path names are equal.
A program that demonstrates this is given as follows −
Example
import java.io.File;
public class Demo {
public static void main(String[] args) {
File file1 = new File("C:/File/demo1.txt");
File file2 = new File("C:/File/demo1.txt");
if (file1.compareTo(file2) == 0) {
System.out.println("Both the paths are lexicographically equal");
} else {
System.out.println("Both the paths are lexicographically not equal");
}
}
}The output of the above program is as follows −
Output
Both the paths are lexicographically equal
Now let us understand the above program.
The method java.io.File.compareTo() is used to compare the two file paths lexicographically. If 0 is returned by the method, the file paths are lexicographically equal, otherwise not. A code snippet that demonstrates this is given as follows −
File file1 = new File("C:/File/demo1.txt");
File file2 = new File("C:/File/demo1.txt");
if (file1.compareTo(file2) == 0) {
System.out.println("Both the paths are lexicographically equal");
} else {
System.out.println("Both the paths are lexicographically not equal");
}
Updated on: 30-Jul-2019
631 Views
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